What is the work done when a volume increases from 3 liters

to 5 liters at 6 atm of pressure? (Conversion factor: 1 L atm = 100))

-1215.9J is the work done

Explanation:

It is possible to find work done in the change of volume of a gas at constant pressure using:

W = - P*ΔV

Where W is work, P is pressure and V is change in volume}

Replacing:

W = - 6atm * (5L-3L)

W = - 12atmL

As 1atmL = 101,325J, work done in joules is:

-12atmL * (101.325J / atmL) = - 1215.9J is the work done