What volume will be occupied by 40.2 g of neon gas at STP?

44.8 L

Explanation:

1 mole of a gas at s. t. p. occupies a volume of 22.4 L.

Molar mass of Neon is 20.1 g/mol

Number of moles of neon present in 40.2 g = Mass/molar mass

Number of moles = 40.2 / 20.1 = 2 moles.

Therefore, 2 moles of neon gas will occupy 2 * 22.4 L = 44.8 L