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7 October, 06:46

Given that ∆G for the reaction below is - 957.9kj, what is ∆Gf of

H2O?

4NH3 (g) + 4NO (g) + 6H2O (g)

∆Gf, NH3=-16.66kj/mol

∆Gf, NO=86.71kj/mol

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  1. 7 October, 08:42
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    - 228.6 kJ/mol.

    Explanation:

    I got bandz
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