Ask Question
2 March, 03:00

How many grams of potassium nitrate (KNO3) are required to prepare 0.250L of a 0.700 M

solution (KNO3 = 101.102 g/mol)

O 12.5 g

O 31.2g

25.38

17.78

+2
Answers (1)
  1. 2 March, 05:01
    0
    17.78g

    Explanation:

    m/M = C*V

    m/101.102 = 0.7 * 0.25

    m = 101.102*0.7*0.25 = 17.78g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many grams of potassium nitrate (KNO3) are required to prepare 0.250L of a 0.700 M solution (KNO3 = 101.102 g/mol) O 12.5 g O 31.2g ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers