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4 February, 08:20

7. At what temperature would 343.01 g of P2O3 gas occupy 67.5 L if the pressure is 115 kPa?

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  1. 4 February, 09:04
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    26.1°C

    Explanation:

    T = PV / nR = (115 kPa) x (67.5 L) / ((343.01 g P2O3 / (109.94572 g P2O3/mol)) x (8.3144626 L kPa/K mol)) = 299.3 K = 26.1°C
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