If you have 39.5g of Fe2O3 how many grams of co are requried to complete reaction

20.8g

Explanation:

1. Balanced chemical equation

Fe₂O₃ (s) + 3CO (g) → 2Fe (s) + 3CO₂ (g)

2. Convert 39.5g of Fe₂O₃ into moles

#moles = mass in grams / molar mass molar mass of Fe₂O₃ = 159.69 g/mol #moles = 39.5g / 159.69g/mol = 0.24735 mol

3. Moles of CO

i) Mole ratio

3mol CO / 1 mol Fe₂O₃

ii) Set a proportion

3 mol CO / 1 mol Fe₂O₃ = x / 0.24735 mol Fe₂O₃

⇒ x = 0.24735mol Fe₂O₃ * 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO

4. Grams of CO

molar mass CO: 28.01g/mol mass in grams = #moles * molar mass mass = 0.7426mol * 28.01g/mol = 20.8g ← answer