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21 July, 15:08

Using standard free energy of formation values given in the introduction, calculate the equilibrium constant kp of the reaction cl2 (g) + 2no (g) ⇌2nocl (g)

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  1. 21 July, 18:56
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    d G = 2 (dG NOCl) - 2 (dG NO)

    = 2 * 66.08 - 2 * 87.6 = - 43.04 kJ / mol

    dG = - 2.303 RT log K

    -43.04 = - 2.303 RT log K

    7.54 = log K

    K = 3.42 * 10^7

    Kp = k (RT) ^dn

    d n = 2 - 1 - 2 = - 1

    Kp = (3.42 * 10^7) (8.314 * 298) ^-1

    Kp = 1.31 * 10^4
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