A 2.10 L vessel contains 4.65 mol of nitrous oxide (N2O) at 3.82 atm. What will be the pressure of this gas in a container that's half the size?

The answer to your question is 7.64 atm

Explanation:

Data

Volume 1 = V1 = 2.1 l

moles = 4.65

Pressure 1 = P1 = 3.82 atm

Volume 2 = Volume 1/2

Pressure 2 = ?

Process

1. - Calculate the new volume

Volume 2 = 2.10/2

Volume 2 = 1.05 l

2. - Use Boyle's law to find the Pressure

P1V1 = P2V2

-Solve for P2

P2 = P1V1 / V2

-Substitution

P2 = (3.82) (2.1) / 1.05

-Simplification

P2 = 8.022/1.05

-Result

P2 = 7.64 atm