What is the temperature of 100 liter container having 1 mole of an

ideal gas at a pressure of 20 kilopascals

Answer:-

240.558 K

Explanation:-

Number of Moles n = 1

Pressure P = 20 kilopascals = 20 KPa

Volume V = 100 L

We know Universal Gas constant R = 8.314 L kPa K-1 mol-1

Using the relation

PV = nRT

Temperature T = P x V / (n x R)

T = 20 KPa x 100 L / (1 mol x 8.314 L kPa K-1 mol-1)

= 240.558 K