Given the equation representing a reaction:

Cd + NiO2 + 2H20 → Cd (OH) 2 + Ni (OH) 2

Which half-reaction equation represents the oxidation in the reaction?

Cd° + H₂O = > Cd (OH) ₂ + 2e⁻ (Oxidation Half-Rxn)

Explanation:

Oxidation = > Loss of e⁻

Reduction = > Gain of e⁻

(o) (+4) (-2) (+2) (-1) (+2) (-1)

Cd° + NiO₂ + 2H₂O = > Cd (OH) ₂ + Ni (OH) ₂

Cd° + H₂O = > Cd (OH) ₂ + 2e⁻ (Oxidation Half-Rxn)

NiO₂ + H₂O + 2e⁻ = > Ni (OH) ₂ (Reduction Half-Rxn)