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21 October, 14:48

A 2.40 L volume of air has a pressure of 101.7 kPa. If initially the pressure of the air was 101.01 kPa, what was the initial volume of air? Assume all other properties remain constant.

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  1. 21 October, 15:35
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    2.42 L

    Step-by-step explanation:

    Since all other properties constant, we can use Boyle's Law.

    p₁V₁ = p₂V₂ Divide each side by p₁

    V₁ = V₂ * p₂/p₁

    dа ta:

    p₁ = 101.01 kPa; V₁ = ?

    p₂ = 101.7 kPa; V₂ = 2.40 L

    Calculations:

    V₁ = 2.40 * 101.7/101.01

    V₁ = 2.42 L
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