Ask Question
22 February, 09:03

How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?

+4
Answers (1)
  1. 22 February, 11:54
    0
    Mass = 2.77g

    Explanation:

    Applying

    P=2.09atm, V = 1.13L, R = 0.082, T = 291K, Mm of N2 = 28

    PV=nRT

    NB

    Moles (n) = m/M

    PV=m/M*RT

    m = PVM/RT

    Substitute and Simplify

    m = (2.09*1.13*28) / (0.082*291)

    m = 2.77g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers