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29 November, 03:17

If the kb of a weak base is 3.3 Ã 10-6, what is the ph of a 0.17 m solution of this base?

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  1. 29 November, 05:54
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    The relation between base equilibrium constant and degree of dissociation is

    C x^2 = Kb

    x is degree of dissociation

    C x^2 = 3.3 * 10^-6

    (0.17) x^2 = 3.3 * 10^-6

    x = 4.24 * 10^-3

    Concentration of hydroxyl ion is

    [OH-] = c x = 0.17 * 4.24 * 10^-3 = 0.72 * 10^-3 M

    PoH = - log [OH-] = 2.85

    PH = 14 - pOH = 11.15

    Hence, pH of solution is 11.15
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