Ask Question
20 December, 08:02

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Use StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction ...

2.19 L

3.33 L

3.68 L

5.60 L

+4
Answers (2)
  1. 20 December, 08:22
    0
    The answer is 3.68 L
  2. 20 December, 11:54
    0
    3.68 L

    Explanation:

    use charle's law formula

    v1 (t2) = v2 (t1)

    and convert celsius to kelvin k=C+273.15

    3.5L (313.15K) = v2 (298.15K)

    solve for v2 by dividing 298.15k on both sides

    v2=3.68
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers