What is the molality of a solution prepared by dissolving 82.2 g of ethylene glycol, hoch2ch2oh, in 1.50 l of water? assume the density of water is 1.00 g/ml?

Answer:-

0.883 m

Explanation:-

Molality = Moles per Kg of solvent.

Molar mass of ethylene glycol = 62.07 g / mol.

Number of moles of ethylene glycol = 82.2g / (62.07 g/mol)

= 1.324 moles

Density of water = 1 g/ml = (1/1000kg) / (1/1000litre)

= 1 Kg / litre

Mass of 1.5 litre of water = 1.5 litre x 1 kg / litre

= 1.5 kg

Molality of ethylene glycol = 1.324 moles/1.5 kg

= 0.883 m