what volume would CO2 in problem 1 occupy at STP? problem 1's answer was 1.1x10^3 grams in 1.5x10^25 molecules of CO2

Answer;

= 560 L

Explanation;

1 mole of a gas at STP occupies a volume of 22400 cm³

Theerefore; in this question we find the volume occupied by 1.1x10^3 grams of CO2

1 mole of CO2 = 22.4 L

but, 1 mole of CO2 = 44 g

thus; 44 g = 22.4 L

Hence; 1.1x10^3 grams will occupy

= ((1.1x10^3 grams) / 44) * 22.4

= 560 L