A student collects 625 mL of oxygen at a temperature of 24°C and a pressure of 0.899 atm. How many moles of oxygen did the student collect?

0.023 moles

Explanation:

Given that:

Pressure = 0.899 atm

Temperature = 24 °C

The conversion of T (°C) to T (K) is shown below:

T (K) = T (°C) + 273.15

So,

T = (24 + 273.15) K = 297.15 K

Volume = 625 mL

Also, 1 mL = 10⁻³ L

So, volume = 0.625 L

Moles of the gas = ?

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L. atm/K. mol

Applying the equation as:

0.899 atm * 0.625 L=n * 0.0821 L. atm/K. mol * 297.15 K

⇒n = 0.023 moles