If 0.756L of gas exerts a pressure of 94.6kPa, what would the volume be at standard pressure (101.33kPa) ?

The answer to your question is Volume = 0.7 l

Explanation:

Data

Volume 1 = V1 = 0.746 l

Pressure 1 = P1 = 94.6 kPa

Volume 2 = V2 = ?

Pressure 2 = 101.33 kPa

Process

To solve this process use Boyle's law.

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (94.6 x 0.746) / 101.33

-Simplification

V2 = 70.57 / 101.33

-Result

V2 = 0.696 l ≈ 0.7 l