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16 August, 00:13

If the pOH of a solution is 9.3, what is the [OH-]

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  1. 16 August, 00:35
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    5.012*10^-10

    Explanation:

    [OH-] = 10^-pOH

    [OH-] = 10^-9.3

    [OH-] = 5.012*10^-10
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