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14 January, 17:49

What is the mass of a sample of aluminum that absorbs 596 J of heat when the temperature is raised from 30.0°C to 100.1°C? Specific heat of aluminum = 0.900 J/g oC

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  1. D
    14 January, 20:55
    0
    Answer is: the mass of a sample of aluminum is 9.45 grams.

    ΔT = 100.1°C - 30.0°C.

    ΔT = 70.1°C.; change in temperature of a sample of aluminium.

    Cp (Al) = 0.900 J/g·°C; specific heat capacity for aluminium.

    Q = 596 J; heat absorbed.

    Q = m (Al) · ΔT · Cp (Al).

    m (Al) = Q : (ΔT · Cp (Al)).

    m (Al) = 596 J : (70.1°C · 0.900 J/g·°C).

    m (Al) = 9.45 g; mass of aluminium sample.
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