Determine the Kelvin temperature required for 0.0140 mol of gas to fill a balloon to 1.20L under 0.988 atm a pressure.

T = 1031.30 K

Explanation:

Given dа ta:

Temperature of gas = ?

Number of moles of gas = 0.014 mol

Volume of balloon = 1.20 L

Pressure of gas = 0.988 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

T = PV/nR

T = 0.988 atm * 1.2 L / 0.014 mol * 0.0821 atm. L / mol. K

T = 1.186 atm. L / 0.00115 atm. L/K

T = 1031.30 K