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12 February, 17:37

when you burn 2 L of propane (C3H8) at stp, you find 5.6L of carbon dioxide has been produced what is the percent yeild

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  1. 12 February, 20:08
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    93%

    Explanation:

    First write the balanced reaction

    C3H8 + 5O2 - -> 3CO2 + 4H2O

    2nd, find the theoretical yield

    2L C3H8 (1mol/22.4L) (3 mol CO2/1 molC3H8) (22.4 L / 1mol) = 6L

    3rd, Find percent yield

    %yield = (actual / theoretical) x100 = (5.7/6) x 100 = 93%
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