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3 June, 17:46

Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperature remains constant?

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  1. 3 June, 19:29
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    The answer to your question is P2 = 342 kPa

    Explanation:

    Data

    Pressure 1 = P1 = 155 kPa

    Volume 1 = V1 = 22 l

    Pressure 2 = P2 = ?

    Volume 2 = V2 = 10 l

    Temperature = constant

    Process

    1. - Write the equation of the combined gas law

    P1V1/T1 = P2V2 / T2

    Cancel T1 and T2 because they measure the same

    P1V1 = P2V2

    -Solve for P2

    P2 = P1V1/V2

    2. - Substitution

    P2 = (155 x 22) / 10

    3. - Simplification

    P2 = 3410 / 10

    4. - Result

    P2 = 342 kPa
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