A gas occupies 3.5 L at standard pressure. Find the volume of the gas when the pressure is 1.5 atm.

V2 gas = 2.33 L

Explanation:

assuming ideal gas:

PV = RTn

∴ n gas = 1 mol

∴ P1 standard = 1 atm

∴ V1 gas = 3.5 L

∴ P2 = 1.5 atm ⇒ V2 = ?

state 1:

∴ P1V1 = nRT1

⇒ P1V1/T1 = nR

state 2:

⇒ P2V2/T2 = nR

(1) = (2)

⇒ P1V1/T1 = P2V2/T2

assiming: T1 = T2

⇒ P1V1 = P2V2

⇒ V2 = P1V1/P2

⇒ V2 = ((1 atm) (3.5 L)) / (1.5 atm)

⇒ V2 = 2.33 L