How many moles of HCl would react with 37.1 mL of 0.138 M Sr (OH) 2

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Chemistry

Dominick Mckinney

16 May, 11:39

How many moles of HCl would react with 37.1 mL of 0.138 M Sr (OH) 2

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Answers (1)

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Eric Brennan · Answer 1

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl (aq) + Sr (OH) ₂ → SrCl₂ (aq) + 2H₂O (l).

V (Sr (OH) ₂) = 37.1 mL : 1000 mL/L.

V (Sr (OH) ₂) = 0.0371 L; volume of the strontium hydroxide solution.

c (Sr (OH) ₂) = 0.138 M; molarity of the strontium hydroxide solution.

n (Sr (OH) ₂) = c (Sr (OH) ₂) · V (Sr (OH) ₂).

n (Sr (OH) ₂) = 0.0371 L · 0.138 mol/L.

n (Sr (OH) ₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n (Sr (OH) ₂) : n (HCl) = 1 : 2.

n (HCl) = 2 · n (Sr (OH) ₂).

n (HCl) = 2 · 0.0051 mol.

n (HCl) = 0.0102 mol; amount of the hydrochloric acid.