A gas mixture contains 0.150 mol of oxygen (O2) gas and 0.211 mol of argon (Ar) gas. The total pressure of the mixture is 159 kPa. What is the partial pressure of Ar in the mixture?

Answer;

Partial pressure of Ar = 92.934 kPa

Explanation;

Partial pressure of a gas = Mole fraction * Total pressure

Mole fraction = Number of moles of a gas / Total moles of gas

Therefore;

Mole fraction of Ar = 0.211 mol / (0.211 + 0.150)

= 0.5845

Total pressure = 159 kPa

Hence;

Partial pressure of Ar = 0.5845 * 159 kPa

= 92.934 kPa