Suppose that the pressure of 0.66 L of gas is 424.9 mm Hg when the temperature is 261.2 K. At what temperature is the volume 7.63 L and the pressure 872.15 mm Hg?

Select one:

a. 6200

b. 1.24e4

c. 3010

d. 11.0

Option a. 6200 K

Explanation:

1) dа ta:

V₁ = 0.66 liter P₁ = 42.9 mmHg T = 261.2 K

T₂ = ? V₂ = 7.63 liter P₂ = 872.15 mmHg

2) Formula:

Combined law of gases:

P₁ V₁ / T₁ = P₂ V₂ / T₂

3) Solution:

Solve for T₂:

T₂ = P₂ V₂ T₁ / (P₁ V₁)

Substitute:

T₂ = 872.15 mmHg * 7.63 liter * 261.2 K / (424.9 mmHg * 0.66 liter)

T₂ = 6198 K

Rounding to 2 significant figures, that is 6200 K, which is the first choice.

I believe it's a. 6200