How many moles of sodium nitrate NaNO3 would be produced from the complete reaction of 253 g sodium chromate Na2CrO4

Answer;

= 3.12 moles of NaNO3

Explanation;

The equation for the reaction is;

Pb (NO3) 2+Na2CrO4 → PbCrO4+2NaNO3

Molar ratios in the reaction are; 1 : 1 : 1 : 2

Which means; One mole of (Na2CrO4) produces two moles of (NaNO3)

We can calculate the number of moles of Na2CrO4,

Moles (na2CrO4) = 253g / 162

= 1.56 moles

Moles of NaNO3 will be;

= 1.56 moles x 2 = 3.12 moles

Therefore, the moles of NaNO3 that will be produced will be 3.12 moles

Answer: 3.12

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