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13 November, 01:15

How many grams of sodium chloride can be produced from 46.3 g of sodium hydroxide?

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  1. 13 November, 02:51
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    =67.65 grams of sodium chloride.

    Explanation:

    In this explanation, we shall assume that the limiting reagent was NaOH only and the amount of HCl used was sufficient.

    NaOH + HCl → NaCl + H₂O

    In the equation, the ratio of NaOH used to the NaCl produced will be 1:1

    The number of moles of NaOH in 46.3 g.

    Number of moles = mass/RMM

    =46.3g/40g/mol

    =1.1575 moles.

    Since the reaction ratio is 1:1, the Number of moles of NaCl produced is also 1.1575 moles.

    The mass of 1.1575 moles of NaCl is: 1.1575 moles * 58.443g/mol

    =67.65 grams of sodium chloride.
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