Suppose you have a. 70 L solution with a. 33 M HCl solution, what would the concentration of the solution be if you add 50 ml of water.

0.31M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial Volume of solution (V1) = 0.7L

Initial concentration (C1) = 0.33M

Final volume (V2) = 50mL + 0.7L

Recall:

1000mL = 1L

50mL = 50/1000 = 0.05L

Final volume (V2) = 0.05 + 0.7 = 0.75L

Final concentration (C2) = ... ?

Step 2:

Determination of the concentration of the diluted solution.

Using the dilution formula, the concentration of the diluted solution can be obtained as follow:

C1V1 = C2V2

0.33 x 0.7 = C2 x 0.75

Divide both side by 0.75

C2 = (0.33 x 0.7) / 0.75

C2 = 0.31M

Therefore, the concentration of the diluted solution is 0.31M