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16 May, 03:20

CHEM AGAIN

Methanol (CH3OH) is an important industrial compound that is produced from the reaction:

CO (g) + H2 (g) - > CH3OH (g)

What mass of CO would be needed to produce 208 kg of methanol?

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Answers (1)
  1. 16 May, 03:30
    0
    Answer:-

    182 Kg

    Explanation:-

    Molar mass of CO = 12 x 1 + 16 x 1 = 28 grams

    Molar mass of CH3OH = 12 x 1 + 1 x 3 + 16 x 1 + 1 x 1

    = 32 grams

    The balanced equation for this reaction is

    CO (g) + H2 (g) - > CH3OH (g)

    From the equation we see

    1 CH3OH is produced from 1 CO

    32 grams of CH3OH is produced from 28 grams of CO.

    208 Kg of CH3OH is produced from (28 gram x 208 Kg) / (32 gram)

    = 182 Kg of CO
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