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6 January, 14:46

How much concentrated 5.24M sulfuric acid is need to prepare 4.4 mL of a 5.29M solution

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  1. 6 January, 16:20
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    V1 = 4.44ml

    Explanation:

    C1 = 5.24M V2=?, C2 = 5.29, V2 = 4.4ml

    Applying dilution formula

    C1V1=C2V2

    5.24*V1 = 5.29*4.4

    V1 = 4.44ml
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