Gas law problem: A gas has a volume of 800 mL at - 25℃ and 600 kPa. What would the volume of the gas be at 227℃ and 1000 kPa?

Answer;

= 930.23 mL

Explanation;

Using the combined gas law;

P1V1/T1 = P2V2/T2

Where; P1 = 600 kPa, V1 = 800 mL, and T1 = - 25 + 273 = 258 K, and

V2=?, P2 = 1000 kPa, and T2 = 227 + 273 = 500 K

Thus;

V2 = P1V1T2/T1P2

= (600 * 800 * 500) / (258 * 1000)

= 930.23 mL