How much heat is required to raise the temperature of a 4.33-g sample of iron (specific heat = 0.450 J/g°C) from 25.0°C to 79.8°C?

106.78 J of heat is required by the iron sample.

Explanation:

We have to find the amount of heat required using the formula,

q = m * c * ΔT

where q is the heat absorbed

m is mass of the metal in grams = 4.33 g

c = specific heat of iron = 0.450 J/g °C

ΔT = change in temperature = 79.8° C - 25°C = 54.8° C

Plugin the values in the above formula, we will get,

q = 4.33 g * 0.450 J/g° C * 54.8° C

= 106.78 J

So 106.78 J of heat is required by the sample of iron.