What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K

28.2 kPa on edge uwu

0.0443 atm

Explanation:

1) dа ta:

a) n = 0.540 mol

b) V = 35.5 liter

c) T = 223 K

2) Formula:

Ideal gas equation: PV = nRT

Where,

P = pressure V = volume n = number of moles T = absolute temperature (kelvin scale) R = universal gas constant = 0.08203 atm-liter/K-mol

3) Calculations:

Solve for P

PV = nRT ⇒ P = nRT/V

Substitute and compute:

P = 0.540 mol * 0.08206 atm-liter/K-mol * 223 K / 35.5 liter

P = 0.0443 atm (you must use 3 significant figures).