3CuCl (aq) + 2Al (s) - AICI3 (aq) + 3Cu (s)

How many grams of Cu will result from the complete reaction of

1.00 g Al in the reaction shown in the equation above?

3.53 grams

Explanation:

First, convert mass of Al to moles:

1.00 g Al * (1 mol Al / 27.0 g Al) = 0.0370 mol Al

Then, use stoichiometry to find moles of Cu:

0.0370 mol Al * (3 mol Cu / 2 mol Al) = 0.0556 mol Cu

Finally, convert moles of Cu to mass:

0.0556 mol Cu * (63.5 g Cu / mol Cu) = 3.53 g Cu