The interior of a refrigerator has a volume of 0.600 m3. the temperature inside the refrigerator in 282 k, and the pressure is 101 kpa. if the molecular weight of air is 29 g/mol, what is the mass of air inside the refrigerator? the ideal gas constant is r = 8.314 j/mol ∙ k = 0.0821 l ∙ atm/mol ∙ k.

In this instance we can use the ideal gas law equation to find the number of moles of gas inside the refrigerator

PV = nRT

where

P - pressure - 101 000 Pa

V - volume - 0.600 m³

n - number of moles

R - universal gas constant - 8.314 J/mol. K

T - temperature - 282 K

substituting these values in the equation

101 000 Pa x 0.600 m³ = n x 8.314 J/mol. K x 282 K

n = 25.8 mol

there are 25.8 mol of the gas

to find the mass of gas

mass of gas = number of moles x molar mass of gas

mass = 25.8 mol x 29 g/mol = 748.2 g

mass of gas present is 748.2 g