When 96 grams of water are produced how many grams of hydrogen must react according to the equation 2H2+O2 react to form 2H2O?

The number of grams of hydrogen that must react according to equation is 10.66 grams

2 H2 + O2 = 2H2O

calculation

find the number of moles of H2O reacted

that is moles = mass/molar mass

molar mass for water = 16 + (1 x2) = 18 g/mol

moles is therefore = 96 g/18 g/mol = 5.33 moles

by use of mole ratio between H2 to H20 which is 2:2 or 1:1 the moles of H2 is also = 5.33 moles

mass of H2 is = moles x molar mass of H2 = 1 x2 = 2g/mol

= 5.33 moles x 2 g/mol = 10.66 grams