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1 January, 14:02

A gas that has a volume of 28 liters, a temperature of 45C, And an unknown pressure has its volume increased to 34 liters and it's temperature decreased to 35C. If I measure the power after the change to be 2.0 ATM, what was the original pressure of the gas? Don't forget to use the right units in your answer.

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  1. 1 January, 17:26
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    P1 = 2.5ATM

    Explanation:

    V1 = 28L

    T1 = 45°C = (45 + 273.15) K = 318.15K

    V2 = 34L

    T2 = 35°C = (35 + 273.15) K = 308.15K

    P1 = ?

    P2 = 2ATM

    applying combined gas equation,

    P1V1 / T1 = P2V2 / T2

    P1*V1*T2 = P2*V2*T1

    Solving for P1

    P1 = P2*V2*T1 / V1*T2

    P1 = (2.0 * 34 * 318.15) / (28 * 308.15)

    P1 = 21634.2 / 8628.2

    P1 = 2.5ATM

    The initial pressure was 2.5ATM
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