How many atoms of chromium are in 0.86 mol of potassium chromate (K2CrO4) ?

Question

Chemistry

Manuel Maxwell

19 May, 23:12

How many atoms of chromium are in 0.86 mol of potassium chromate (K2CrO4) ?

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Fernanda Morse · Answer 1

Atoms of Cr in 0.86 mol of K2CrO4 = 0.86 * 6.02*10^23 = 5.177 * 10^23 atoms.

Explanation: One mol of K2CrO4 contains 6.02*10^23 molecules of K2CrO4. One K2CrO4 contains 1 atom of Cr. So 0.86 mol of K2CrO4 contain 0.86 * 6.02*10^23. Which is equal to 5.177 * 10^23 atoms.