When 24.9 grams of ethane (C2H6) react with excess oxygen to produce carbon dioxide, the percent yield is 56.8%. What was the actual yield of the reaction? 2C2H6 + 7O2 4CO2 + 6H2O

Answer: actual yield = 41.4 g

Explanation:

Reaction hydrocarbons with excess Oxygen is called Combustion reaction.

To find the actual yield, we need to know thereotical yield.

Theoretical yield:

(24.9 g C2H6/30 g/mol C2H6) X (4 molCO2/2 mol C2H6) X (44 g CO2/1 mol CO2)

= 73.04 g Co2

%yield = observed yiled x100/theoretical yield

Observed yield = %yieldxtheoretical yield/100

= 56.8x73.04/100

= 41.4 g