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14 March, 02:13

Calculate the mass of sodium acetate trihydrate required to make 100. mL of a 0.100 M solution. 0.820 g 1.00 g 1.36 g 1.95 g

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  1. 14 March, 05:44
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    1.36 g.

    Explanation:

    First we calculate the molar mass of sodium acetate trihydtrate:

    CH3COONa. 3H2O

    = 12 + 3 + 12 + 2*16 + 23 + 6 + 3*16

    = 136 g.

    So 1 L of 1 M solution contains 136 g

    0.100 M solution will contain 13.6 g

    100 mL of 0.100 M solution contains 1.36 g.
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