A gas has pressure of 50.0 mmHG at a temperature of 540K. What will be the temperature if the pressure goes down to 3 mmHG

32.4 K

Explanation:

From the given parameters;

Initial pressure P1 = 50.0 mmHg

Initial temperature T1 = 540K

Final Temperature T2 = ?

Final pressure P2=3 mmHg

Now using this relationship;

P1/T1 = P2/T2

We have; P1T2 = P2T1

Hence;

T2 = P2T1/P1

T2 = 3 * 540/50.0

T2 = 32.4 K