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15 January, 12:50

At a certain temperature the rate of this reaction is first order in HI with a rate constant of : 7.21/s2HI (g) = H2 (g) + I2 (g) Suppose a vessel contains HI at a concentration of 0.440M. Calculate the concentration of HI in the vessel 0.210 seconds later. You may assume no other reaction is important.

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  1. 15 January, 13:50
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    C HI = 0.0968 M

    Explanation:

    2HI (g) → H2 (g) + I2 (g) - ra = K (Ca) ∧α = - δCa/δt

    ∴ a: HI (g)

    ∴ order (α) = 1

    ∴ rate constant (K) = 7.21/s

    ∴ Initial concenttration HI (g) (Cao) = 0.440 M

    ∴ t = 0.210 s ⇒ Ca = ?

    ⇒ - δCa/δt = KCa

    ⇒ - ∫δCa/Ca = K*∫δt

    ⇒ Ln (Cao/Ca) = K*t

    ⇒ Cao/Ca = e∧ (K*t)

    ⇒ Cao/e∧ (K*t) = Ca

    ⇒ Ca = (0.440) / e∧ ((7.21*0,21))

    ⇒ Ca = 0.440/4.54533

    ⇒ Ca = 0.0968 M
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