What is the volume of 15.2 grams of SO2 at STP?

5.33 Liters is the volume of 15.2 grams of SO2 at STP.

Explanation:

If the mass of the gas, then you can divide the mass by the molecular weight of the gas molecules to get the number of moles. Then multiply this by 22.4 Liters / mole to get the volume.

PV = nRT = > The Ideal Gas Law.

Each unit occurs three times and the cube root yields L-atm / mol-K, the correct units for R when used in a gas law context.

PV / nT = R. or PV = nRT.

R is called the gas constant.

PV = nRT = > V = nRT/P

n = moles SO₂ = 15.2g/64g·mol⁻¹ = 0.238 mole

R = Gas Constant = 0.08206 L·atm/mol·K

T = Kelvin Temp = 273K at STP

P = pressure in atmospheres = 1.0 atm at STP

∴ V = (0.238mol) (0.08206 L·atm/mol·K) (273K) / (1.0atm)

=> 5.33 Liters SO₂.