For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol?

Question

Chemistry

Holt

4 February, 07:26

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol?

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Answers (1)

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Pranav Sutton · Answer 1

Q = 245 = 2.5 * 10^2

Explanation:

ΔG = ΔGº + RTLnQ, so also ΔGº = - RTLnK

R = 8,314 J/molK, T=298K

ΔGº = - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

ΔG = ΔGº + RTLnQ → - 20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol * LnQ

→ 5.5 = LnQ → Q = 245 = 2.5 * 10^2