A 50 gram object with a specific heat of 0.3825 J/g*C releases 4593 joules of heat.

If the initial temperature was 235.16C, calculate the final temperature.

475.26°C

Explanation:

Given parameters:

Mass of object = 50g

Specific heat = 0.3825J/g°C

Quantity of heat = 4593Joules

Initial temperature = 235.16°C

Unknown:

Final temperature = ?

Solution:

The quantity of heat absorbed by a body is a function of the mass, specific heat capacity and temperature change the body undergoes.

Mathematically, this relationship is given as;

H = m c Ф

where H is the quantity of heat

m is the mass of the body

c is the specific heat capacity

Ф is the temperature difference

Ф = final temperature - initial temperature

Since we are solving for final temperature, let us substitute for other given parameters;

H = m c (final temperature - initial temperature)

4593 = 50 x 0.3825 x (F - 235.16)

F - 235.16 = 240.1

F = 240.1 + 235.16 = 475.26°C