What volume would 4.3 moles of hydrogen gas occupy at 45° C and 3.22 atm?

34.82 L

Explanation:

Step 1:

Data obtained from the question:

Number of mole (n) = 4.3 mole

Temperature (T) = 45°C = 45°C + 273 = 318K

Pressure (P) = 3.22 atm

Volume (V) = ?

Step 2:

Determination of the volume hydrogen gas.

With the application of the ideal gas equation, the volume of Hydrogen gas can be obtained as follow:

Note that the gas constant (R) = 0.082atm. L/Kmol

PV = nRT

3.22 x V = 4.3 x 0.082 x 318

Divide both side by 3.22

V = (4.3 x 0.082 x 318) / 3.22

V = 34.82 L

Therefore the volume occupied by the hydrogen gas is 34.82 L

34.8 L of hydrogen gas

Explanation:

Now we have to use the ideal gas equation;

PV = nRT

P = pressure of the gas = 3.22atm

V = volume of the gas = ?

T = temperature of the gas = 45°C + 273 = 318K

n = number of moles = 4.3 moles

R = universal gas constant = 0.082atm Lmol-1K-1

Making V the subject of the formula

V = nRT/P

V = 4.3*0.082*318/3.22

V = 34.8 L