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A flexible vessel contains 43L of gas where the pressure is 1.3 atm. What will the volume be when the pressure is 0.61 atm, the temperature remaining constant?

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  1. Today, 01:52
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    91.64L

    Explanation:

    Step 1:

    Data obtained from the question.

    This includes the following:

    Initial volume (V1) = 43L

    Initial pressure (P1) = 1.3 atm

    Final volume (V2) = ... ?

    Final pressure (P2) = 0.61 atm

    Step 2:

    Determination of the final volume.

    To solve for the final volume, we'll apply the Boyle's law equation since the temperature is constant. The final volume is obtained as follow:

    P1V1 = P2V2

    1.3 x 43 = 0.61 x V2

    Divide both side by 0.61

    V2 = (1.3 x 43) / 0.61

    V2 = 91.64L

    Therefore, the new volume is 91.64L
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