A sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 802 torr. If the pressure changes to 4010 torr, with no change in the temperature or moles of gas, what is the new volume, V 2?

The new volume is 2.4 L

calculation

The new volume is calculated using Boyle's law formula

That is P₁V₁=P₂V₂

where,

p₁ = 802 torr

V₁ = 12.0 l

P₂ = 4010 torr

V₂=?

make V₂ the subject of the formula by diving both side of equation by P₂

V₂ = P₁V₁/P₂

V₂ is therefore = { (12.0 l * 802 torr) 4010 torr} = 2.4 L